1.
To fetch ALTERNATE records from a table. (EVEN NUMBERED)
select * from emp where rowid in (select decode(mod(rownum,2),0,rowid, null) from emp);
select * from emp where rowid in (select decode(mod(rownum,2),0,rowid, null) from emp);
2.
To select ALTERNATE records from a table. (ODD NUMBERED)
select * from emp where rowid in (select decode(mod(rownum,2),0,null ,rowid) from emp);
select * from emp where rowid in (select decode(mod(rownum,2),0,null ,rowid) from emp);
3.
Find the 3rd MAX salary in the emp table.
select distinct sal from emp e1 where 3 = (select count(distinct sal) from emp e2 where e1.sal <= e2.sal);
select distinct sal from emp e1 where 3 = (select count(distinct sal) from emp e2 where e1.sal <= e2.sal);
4.
Find the 3rd MIN salary in the emp table.
select distinct sal from emp e1 where 3 = (select count(distinct sal) from emp e2where e1.sal >= e2.sal);
select distinct sal from emp e1 where 3 = (select count(distinct sal) from emp e2where e1.sal >= e2.sal);
5.
Select FIRST n records from a table.
select * from emp where rownum <= &n;
select * from emp where rownum <= &n;
6.
Select LAST n records from a table
select * from emp minus select * from emp where rownum <= (select count(*) - &n from emp);
select * from emp minus select * from emp where rownum <= (select count(*) - &n from emp);
7.
List dept no., Dept name for all the departments in which there
are no employees in the department.
select * from dept where deptno not in (select deptno from emp);
alternate solution: select * from dept a where not exists (select * from emp b where a.deptno = b.deptno);
altertnate solution: select empno,ename,b.deptno,dname from emp a, dept b where a.deptno(+) = b.deptno and empno is null;
select * from dept where deptno not in (select deptno from emp);
alternate solution: select * from dept a where not exists (select * from emp b where a.deptno = b.deptno);
altertnate solution: select empno,ename,b.deptno,dname from emp a, dept b where a.deptno(+) = b.deptno and empno is null;
8.
How to get 3 Max salaries ?
select distinct sal from emp a where 3 >= (select count(distinct sal) from emp b where a.sal <= b.sal) order by a.sal desc;
select distinct sal from emp a where 3 >= (select count(distinct sal) from emp b where a.sal <= b.sal) order by a.sal desc;
9.
How to get 3 Min salaries ?
select distinct sal from emp a where 3 >= (select count(distinct sal) from emp b where a.sal >= b.sal);
select distinct sal from emp a where 3 >= (select count(distinct sal) from emp b where a.sal >= b.sal);
10. How to get nth max
salaries ?
select distinct hiredate from emp a where &n = (select count(distinct sal) from emp b where a.sal >= b.sal);
select distinct hiredate from emp a where &n = (select count(distinct sal) from emp b where a.sal >= b.sal);
11. Select DISTINCT
RECORDS from emp table.
select * from emp a where rowid = (select max(rowid) from emp b where a.empno=b.empno);
select * from emp a where rowid = (select max(rowid) from emp b where a.empno=b.empno);
12. How to delete
duplicate rows in a table?
delete from emp a where rowid != (select max(rowid) from emp b where a.empno=b.empno);
delete from emp a where rowid != (select max(rowid) from emp b where a.empno=b.empno);
13. Count of number of
employees in department wise.
select count(EMPNO), b.deptno, dname from emp a, dept b where a.deptno(+)=b.deptno group by b.deptno,dname;
select count(EMPNO), b.deptno, dname from emp a, dept b where a.deptno(+)=b.deptno group by b.deptno,dname;
14. Suppose there is
annual salary information provided by emp table. How to fetch monthly salary of
each and every employee?
select ename,sal/12 as monthlysal from emp;
15. Select all record from
emp table where deptno =10 or 40.
select * from emp where deptno=30 or
deptno=10;
16. Select all record from
emp table where deptno=30 and sal>1500.
select * from emp where deptno=30 and
sal>1500;
17. Select all
record from emp where job not in SALESMAN or CLERK.
select * from emp where job not in
('SALESMAN','CLERK');
18. Select all record from
emp where ename in 'BLAKE','SCOTT','KING'and'FORD'.
select * from emp where ename
in('JONES','BLAKE','SCOTT','KING','FORD');
19. Select all records
where ename starts with ‘S’ and its lenth is 6 char.
select * from emp where ename like'S____';
20. Select all records
where ename may be any no of character but it should end with ‘R’.
select * from emp where ename like'%R';
21. Count MGR and
their salary in emp table.
select count(MGR),count(sal) from emp;
22. In emp table add
comm+sal as total sal .
select ename,(sal+nvl(comm,0)) as totalsal
from emp;
23. Select any
salary <3000 from emp table.
select * from emp where sal>
any(select sal from emp where sal<3000);
24. Select all
salary <3000 from emp table.
select * from emp where sal>
all(select sal from emp where sal<3000);
25. Select all the
employee group by deptno and sal in descending order.
select ename,deptno,sal from emp order by
deptno,sal desc;
26. How can I create an
empty table emp1 with same structure as emp?
Create table emp1 as select * from emp where
1=2;
27. How to retrive record
where sal between 1000 to 2000?
Select * from emp where sal>=1000 And sal<2000
Select * from emp where sal>=1000 And sal<2000
28. Select all records
where dept no of both emp and dept table matches.
select * from emp where exists(select * from dept where emp.deptno=dept.deptno)
select * from emp where exists(select * from dept where emp.deptno=dept.deptno)
29. If there are two
tables emp1 and emp2, and both have common record. How can I fetch all the
recods but common records only once?
(Select * from emp) Union (Select * from emp1)
(Select * from emp) Union (Select * from emp1)
30. How to fetch only
common records from two tables emp and emp1?
(Select * from emp) Intersect (Select * from emp1)
(Select * from emp) Intersect (Select * from emp1)
31. How can I
retrive all records of emp1 those should not present in emp2?
(Select * from emp) Minus (Select * from emp1)
(Select * from emp) Minus (Select * from emp1)
32. Count the
totalsa deptno wise where more than 2 employees exist.
SELECT deptno, sum(sal) As totalsal
FROM emp
GROUP BY deptno
HAVING COUNT(empno) > 2
SELECT deptno, sum(sal) As totalsal
FROM emp
GROUP BY deptno
HAVING COUNT(empno) > 2
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